n=3(k^3+k-2)+3r

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Solution for n=3(k^3+k-2)+3r equation: 


Simplifying
n = 3(k3 + k + -2) + 3r

Reorder the terms:
n = 3(-2 + k + k3) + 3r
n = (-2 * 3 + k * 3 + k3 * 3) + 3r
n = (-6 + 3k + 3k3) + 3r

Solving
n = -6 + 3k + 3k3 + 3r

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Simplifying
n = -6 + 3k + 3k3 + 3r

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